0=(8x^-2)+3

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Solution for 0=(8x^-2)+3 equation: 



0=(8x^-2)+3

We move all terms to the left:

0-((8x^-2)+3)=0

We add all the numbers together, and all the variables

-((8x^-2)+3)=0



We calculate terms in parentheses: -((8x^-2)+3), so:

(8x^-2)+3

We get rid of parentheses

8x^-2+3

We add all the numbers together, and all the variables

8x+1

Back to the equation:

-(8x+1)



We get rid of parentheses

-8x-1=0

We move all terms containing x to the left, all other terms to the right

-8x=1

x=1/-8

x=-1/8

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